SELECT COUNT (DISTINCT A||B) FROM TABLE --distinct at a time in a table
Query to find the employees in a department having maximum number of emps
SELECT e.empno, e.ename, e.sal, e.deptno
FROM emp e
, (
SELECT deptno
, RANK () OVER (ORDER BY COUNT (*) DESC) AS rnk
FROM emp
GROUP BY deptno
) s
WHERE e.deptno = s.deptno
AND s.rnk = 1
;
Or
select empno, ename, sal, a.deptno
from emp a,
(select deptno from (select deptno, count(1) over (partition by (deptno)) from emp order by 2 desc) where rownum =1) b
where a.deptno = b.deptno;
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